## Description

## BPHCT-137 WAVES AND OPTICS

## Solved Assignment 2020-2021

Tutor Marked Assignment

WAVES AND OPTICS

Course Code: BPHCT-137

Assignment Code: BPHCT-137/TMA/2021

Max. Marks: 100

Title Name |
BPHCT-137 Solved Assignment 2020-2021 |

University |
IGNOU |

Service Type |
Solved Assignment (Soft copy/PDF) |

Course |
BSCG |

Language |
ENGLISH |

Semester |
2020-2021 Course: B.SC(G) CBCS |

Session |
2020-21 |

Short Name |
BPHCT-137 (ENGLISH) |

Assignment Code |
BPHCT-137/TMA/2021 |

Product |
Assignment of BSCG 2020-2021 (IGNOU) |

Submission Date |
This assignment is valid from 1st January, 2021 to 31st December, 2021. If you have failed in this assignment or fail to submit it by 31st December, 2021, then you need to get the assignment for the year 2022, and submit it as per the instructions given in the Programme Guide. |

Price |
RS. 50 |

1. a) The mathematical expression for one dimensional wave travelling along the

positive x-direction is given as

y(x,t) 0.02 sin(42 x 1886t)m

where x is in meters and t is in seconds. Determine the direction of propagation of

the wave and calculate its amplitude, wavelength, frequency and velocity. (25)

b) Determine the frequencies of the fundamental mode and the next two harmonics

that can be set up on a sitar string of length 1.0 m. Take the speed of waves of the

string to be 2.8 10 ms . 3 1 (5)

c) The electric field vectors of two light waves propagating along the positive zdirection are given as

E1(z,t) xˆ E01cos(kz t)

E2(z,t) yˆ E02cos(kz t )

where xˆ and yˆ are unit vectors along x and y-axes, respectively. Show that when

these two waves superpose, we obtain elliptically polarised light. Also show that

the linear and circular polarisations are special cases of elliptical polarisation. (5+5)

2. a) Derive an expression for the displacement of the nth bright fringe in Young’s

double-slit experiment when a thin transparent plate of refractive index and

thickness t is introduced in the path of one of the constituent interfering beams of

light. Will there be any change in the fringe-width after the introduction of the

plate? (8+2)

b) i) Distinguish between fringes of equal inclination and fringes of equal thickness. (5)

ii) Newton’s rings are formed in reflected light of wavelength 5890 108 cm with a

liquid between the plane and curved surfaces. The diameter of the fifth ring is

0.3 cm and the radius of curvature of the curved surface is 100 cm. Calculate

the refractive index of the liquid, when the ring is bright. (5)

c) Explain how Michelson interferometer is used to determine the refractive index of a

thin plate. (5)

PART B

3. a) What is a zone plate? How does a positive zone plate differ from a negative zone

plate? Show that each Fresnel zone has nearly the same area. (3+3+4)

4

b) In the Fraunhofer diffraction pattern due to a single slit, the intensity of the central

spot is maximum. Explain on the basis of geometrical considerations. (5)

c) The Fraunhofer diffraction pattern due to a single slit of width 0.4 cm is obtained

with the help of a lens of focal length 30 cm. If the wavelength of light used is

5890 Å, calculate the distance of the first dark fringe and the consecutive bright

fringe from the axis. (5)

d) The radius of the fifth zone of a zone plate is 2 mm. Considering the zone plate as

a converging lens, calculate its focal length for light of wavelength 4800 Å. (5)

4. a) What do you understand by spatial and temporal coherence? (3)

b) Explain the meaning of coherence length. (3)

c) What is the difference between spontaneous emission of radiation and stimulated

emission of radiation? (3)

d) How is holography different from ordinary photography? (3)

e) What are the advantages of using optical fibre as communication medium? (3)

5. a) In a laser, the lasing levels are the first excited state and the ground state of the

active medium. If the energy of the first excited state is 1.5eV, calculate the

frequency of the laser light. (5)

b) The refractive index of the core and cladding materials of an optical fibre is 1.46

and 1.38, respectively. Calculate the critical angle, numerical aperture and

acceptance angle at the air-fibre interface.

BPHCT-137, BPHCT 137, BPHCT137

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